Use the necessary constant in solving this problem. See second photo. Transcribed Image Text: Calculate the amount in grams of ammonium acetate needed to form 342 mL of 2.6 M solution
Atomic Mass:
C: 12.011 g/mol
H: 1.008 g/mol
O: 15.999 g/mol
N: 14.007 g/mol
Round your answer to 2 decimal places. Transcribed Image Text: Units oF Pressure
760mm Hg
1 atm
1 atm
760 torr
1 atm – 101 , 325 Pa
1 atm =
14.7 pei
univercal gar conctant
-R= 0.08 206 L
atm
mo/ k-1
– used in most gas
equations
8. 314
-R =
-1
mol
– uved in equations
involving energY
1 mol gas STP= 22.41 L